Question

A projectile is shot from the ground at a velocity of `8 m/s` at an angle of `pi/6`. How long will it take for the projectile to land?

Answer 1

The time is `0.8`s

Explanation:

Use the formula
`s=u_ot-(1/2)g t^2`

`s=0`
`u_o=8sin(pi/6)`
and `t` is the time

`t=0`

or `t=(8*2)sin(pi/6)/g=16sin(pi/6)/g`

`sin(pi/6)=1/2` and `g=10`
So `t=(16/10)1/2=0.8 s`