A projectile is shot from the ground at a velocity of $8 m/s$ at an angle of $pi/6$ . How long will it take for the projectile to land?

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Answer 1 · 2016-10-24T09:40:08

The time is $0.8$ s

Use the formula
$s=u_ot-(1/2)g t^2$

$s=0$
$u_o=8sin(pi/6)$
and $t$ is the time

$t=0$

or $t=(8*2)sin(pi/6)/g=16sin(pi/6)/g$

$sin(pi/6)=1/2$ and $g=10$
So $t=(16/10)1/2=0.8 s$

A projectile is shot from the ground at a velocity of 8 m/s8 m/s at an angle of pi/6pi/6. How long will it take for the projectile to land?