Question

A projectile is shot from the ground at a velocity of `9 m/s` and at an angle of `(5pi)/6`. How long will it take for the projectile to land?

Answer 1

`T=0.9184s`

Explanation:

Data:-
Muzzle velocity`=`Initial velocity`=v_0=9m/s`
Angle`=theta=(5pi)/6`
Time of flight`=T=??`
Sol:-
`T=(2v_0Sintheta)/g`

`implies T=(2*9sin((5pi)/6))/9.8=(18*0.5)/9.8=9/9.8=0.9184s`

`implies T=0.9184s`