A solid disk, spinning counter-clockwise, has a mass of $12 k g$ $12 kg$ and a radius of $6 m$ $6 m$ . If a point on the edge of the disk is moving at $15 \frac{m}{s}$ $15 m/s$ in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?

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A solid disk, spinning counter-clockwise, has a mass of $12 k g$ $12 kg$ and a radius of $6 m$ $6 m$ . If a point on the edge of the disk is moving at $15 \frac{m}{s}$ $15 m/s$ in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?

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Answer 1 · 2016-12-25T09:09:37

The angular momentum is $= 720 π = 2262 k g m^{2} s^{- 1}$ $=720pi=2262kgm^2s^(-1)$
The angular velocity is $= \frac{10 π}{3} = 10.5 r a d s^{- 1}$ $=(10pi)/3 =10.5rads^(-1)$

Explanation:

The angular velocity,

$ω = \frac{v}{r} = \frac{15}{6} H z = \frac{5}{3} \cdot 2 π r a d s^{- 1} = \frac{10 π}{3} r a d s^{- 1}$ $omega=v/r=15/6Hz=5/3*2pirads^(-1)=(10pi)/3 rads^(-1)$

The angular momentum is

$L = I ω$ $L=Iomega$

Where $I$ $I$ is the moment of inertia

For a solid disc, $I = \frac{1}{2} \cdot m \cdot r^{2}$ $I=1/2*m*r^2$

$I = \frac{1}{2} \cdot 12 \cdot 6^{2} = 216 k g m^{2}$ $I=1/2*12*6^2=216 kgm^2$

The angular momentum is

$L = 216 \cdot \frac{10 π}{3} = (720 π) k g m^{2} s^{- 1}$ $L=216*(10pi)/3=(720pi)kg m^2s^(-1)$

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A solid disk, spinning counter-clockwise, has a mass of $12 k g$ $12 kg$ and a radius of $6 m$ $6 m$ . If a point on the edge of the disk is moving at $15 \frac{m}{s}$ $15 m/s$ in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?

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Explanation:

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A solid disk, spinning counter-clockwise, has a mass of 12 kg12kg12 kg and a radius of 6 m6m6 m. If a point on the edge of the disk is moving at 15 m/s15ms15 m/s in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?

1 Answer

Explanation:

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A solid disk, spinning counter-clockwise, has a mass of $12 k g$ $12 kg$ and a radius of $6 m$ $6 m$ . If a point on the edge of the disk is moving at $15 \frac{m}{s}$ $15 m/s$ in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?