A solid disk, spinning counter-clockwise, has a mass of $14 kg$ and a radius of $5/4 m$ . If a point on the edge of the disk is moving at $2/9 m/s$ in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?

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Answer 1 · 2017-02-18T12:11:52

The angular momentum is $=12.22kgm^2s^(-1)$
The angular velocity is $=1.12rads^-1$

The angular velocity is

$omega=v/r$

where,

$v=2/9ms^(-1)$

$r=5/4m$

So,

$omega=(2/9)/(5/4)*2pi=16/45pi=1.12rads^-1$

The angular momentum is $L=Iomega$

For a solid disc, $I=(mr^2)/2$

So, $I=14*(5/4)^2/2=175/16kgm^2$

$L=1.12*175/16=12.22kgm^2s^(-1)$

A solid disk, spinning counter-clockwise, has a mass of 14 kg14 kg and a radius of 5/4 m5/4 m. If a point on the edge of the disk is moving at 2/9 m/s2/9 m/s in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?