A solid disk, spinning counter-clockwise, has a mass of $2 k g$ $2 kg$ and a radius of $3 m$ $3 m$ . If a point on the edge of the disk is moving at $6 \frac{m}{s}$ $6 m/s$ in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?

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Answer 1 · 2017-04-04T11:39:33

The angular momentum is $= 18 k g m^{2} s^{- 1}$ $=18kgm^2s^-1$ and the angular velocity is $= 2 r a d s^{- 1}$ $=2rads^-1$

The angular velocity is

$omega=(Deltatheta)/(Deltat)$

$v=r*((Deltatheta)/(Deltat))=r omega$

$omega=v/r$

where,

$v=6ms^(-1)$

$r=3m$

So,

$omega=(6)/(3)=2rads^-1$

The angular momentum is $L=Iomega$

For a solid disc, $I=(mr^2)/2$

So, $I=2*(3)^2/2=9kgm^2$

The angular momentum is

$L=9*2=18kgm^2s^-1$

A solid disk, spinning counter-clockwise, has a mass of 2 kg2kg2 kg and a radius of 3 m3m3 m. If a point on the edge of the disk is moving at 6 m/s6ms6 m/s in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?