A solid disk, spinning counter-clockwise, has a mass of $3 k g$ $3 kg$ and a radius of $2 m$ $2 m$ . If a point on the edge of the disk is moving at a rate of $2 \frac{m}{s}$ $2 m/s$ in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?

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Answer 1 · 2017-07-01T05:33:16

The angular momentum is $= 6 k g m^{2} s^{- 1}$ $=6kgm^2s^-1$ and the angular velocity is $= 1 r a d s^{- 1}$ $=1rads^-1$

The angular velocity is

$omega=(Deltatheta)/(Deltat)$

$v=r*((Deltatheta)/(Deltat))=r omega$

$omega=v/r$

where,

$v=2ms^(-1)$

$r=2m$

So,

$omega=(2)/(2)=1rads^-1$

The angular momentum is $L=Iomega$

For a solid disc, $I=(mr^2)/2$

So, $I=3*(2)^2/2=6kgm^2$

The angular momentum is

$L=6*1=6kgm^2s^-1$

A solid disk, spinning counter-clockwise, has a mass of 3 kg3kg3 kg and a radius of 2 m2m2 m. If a point on the edge of the disk is moving at a rate of 2 m/s2ms2 m/s in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?