A solid disk, spinning counter-clockwise, has a mass of $3 kg$ and a radius of $3 m$ . If a point on the edge of the disk is moving at $8 m/s$ in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?

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Answer 1 · 2016-10-25T07:12:05

The disc angular momentum is $36 kg m^2s^(-1)$
And the angular velocity is $(8/3) (rad)/s$

The angular momentum is given by $L=I×omega$
Where $I=$ moment of inertia
And $omega=$ angular velocity

The moment inertia of a disc is given by $I=(mr^2)/2$
where $m=$ mass of the disc
And $r=$ radius of the disc

Also we use the formula $v=r.omega$

So $omega=v/r=8/3 rad/s$

$I=3.3^2/2=27/2 kg m^2$

And the angular momentum is $L=27/2.(8/3)=36 kg m^2s^(-1)$

A solid disk, spinning counter-clockwise, has a mass of 3 kg3 kg and a radius of 3 m3 m. If a point on the edge of the disk is moving at 8 m/s8 m/s in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?