A solid disk, spinning counter-clockwise, has a mass of $3 kg$ and a radius of $4 m$ . If a point on the edge of the disk is moving at a rate of $2 m/s$ in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?

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Answer 1 · 2017-02-24T06:26:02

The angular momentum is $=75.4kgm^2s^-1$
The angular velocity is $=3.14rads^-1$

The angular velocity is

$omega=v/r$

where,

$v=2ms^(-1)$

$r=4m$

So,

$omega=(2)/(4)*2pi=3.14rads^-1$

The angular momentum is $L=Iomega$

For a solid disc, $I=(mr^2)/2$

So, $I=3*(4)^2/2=24kgm^2$

$L=3.14*24=75.4kgm^2s^-1$

A solid disk, spinning counter-clockwise, has a mass of 3 kg3 kg and a radius of 4 m4 m. If a point on the edge of the disk is moving at a rate of 2 m/s2 m/s in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?