A solid disk, spinning counter-clockwise, has a mass of $4 kg$ and a radius of $4 m$ . If a point on the edge of the disk is moving at $12 m/s$ in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?

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Answer 1 · 2017-04-08T05:35:31

The angular momentum is $=96kgm^2s^-1$
The angular velocity is $=3rads^-1$

The angular velocity is

$omega=(Deltatheta)/(Deltat)$

$v=r*((Deltatheta)/(Deltat))=r omega$

$omega=v/r$

where,

$v=12ms^(-1)$

$r=4m$

So,

$omega=(12)/(4)=3rads^-1$

The angular momentum is $L=Iomega$

For a solid disc, $I=(mr^2)/2$

So, $I=4*(4)^2/2=32kgm^2$

The angular momentum is

$L=32*3=96kgm^2s^-1$

A solid disk, spinning counter-clockwise, has a mass of 4 kg4 kg and a radius of 4 m4 m. If a point on the edge of the disk is moving at 12 m/s12 m/s in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?