A solid disk, spinning counter-clockwise, has a mass of $5 k g$ $5 kg$ and a radius of $2 m$ $2 m$ . If a point on the edge of the disk is moving at $8 \frac{m}{s}$ $8 m/s$ in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?

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Answer 1 · 2017-05-07T17:26:09

The angular momentum is $= 40 g m^{2} s^{- 1}$ $=40gm^2s^-1$
The angular velocity is $= 4 r a d s^{- 1}$ $=4rads^-1$

The angular velocity is

$omega=(Deltatheta)/(Deltat)$

$v=r*((Deltatheta)/(Deltat))=r omega$

$omega=v/r$

where,

$v=8ms^(-1)$

$r=2m$

So,

$omega=(8)/(2)=4rads^-1$

The angular momentum is $L=Iomega$

For a solid disc, $I=(mr^2)/2$

So, $I=5*(2)^2/2=10kgm^2$

The angular momentum is

$L=10*4=40gm^2s^-1$

A solid disk, spinning counter-clockwise, has a mass of 5 kg5kg5 kg and a radius of 2 m2m2 m. If a point on the edge of the disk is moving at 8 m/s8ms8 m/s in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?