A solid disk, spinning counter-clockwise, has a mass of $6 kg$ and a radius of $1/5 m$ . If a point on the edge of the disk is moving at $12/5 m/s$ in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?

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Answer 1 · 2018-01-12T07:26:23

The angular momentum is $=1.44kgm^2s^-1$ and the angular velocity is $=12rads^-1$

The angular velocity is

$omega=(Deltatheta)/(Deltat)$

$v=r*((Deltatheta)/(Deltat))=r omega$

$omega=v/r$

where,

$v=12/5ms^(-1)$

$r=1/5m$

So,

The angular velocity is

$omega=(12/5)/(1/5)=12rads^-1$

The angular momentum is $L=Iomega$

For a solid disc, $I=(mr^2)/2$

The mass is $m=6 kg$

So, $I=6*(1/5)^2/2=0.12kgm^2$

The angular momentum is

$L=12*0.12=1.44kgm^2s^-1$

A solid disk, spinning counter-clockwise, has a mass of 6 kg6 kg and a radius of 1/5 m1/5 m. If a point on the edge of the disk is moving at 12/5 m/s12/5 m/s in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?