A solid disk, spinning counter-clockwise, has a mass of $6 kg$ and a radius of $2 m$ . If a point on the edge of the disk is moving at a rate of $2 m/s$ in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?

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Answer 1 · 2016-12-04T09:24:03

The angular momentum is $=12kgms^(-1)$
The angular velocity $=1 Hz$

The angular velocity is

$omega=v/r$

where,

$v=2ms^(-1)$

$r=2m$

So,

$omega=2/2=1Hz$

The angular momentum is $L=Iomega$

For a solid disc, $I=(mr^2)/2$

So, $I=6*2^2/2=12kgm^2$

$L=12*1=12kgms^(-1)$

A solid disk, spinning counter-clockwise, has a mass of 6 kg6 kg and a radius of 2 m2 m. If a point on the edge of the disk is moving at a rate of 2 m/s2 m/s in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?