A solid disk, spinning counter-clockwise, has a mass of $6 kg$ and a radius of $3/5 m$ . If a point on the edge of the disk is moving at $3 m/s$ in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?

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Answer 1 · 2017-05-04T08:21:26

The angular momentum is $=5.4kgm^2s^-1$
The angular velocity is $=5rads^-1$

The angular velocity is

$omega=(Deltatheta)/(Deltat)$

$v=r*((Deltatheta)/(Deltat))=r omega$

$omega=v/r$

where,

$v=3ms^(-1)$

$r=3/5m$

So,

$omega=(3)/(3/5)=5rads^-1$

The angular momentum is $L=Iomega$

For a solid disc, $I=(mr^2)/2$

So, $I=6*(3/5)^2/2=27/25kgm^2$

The angular momentum is

$L=27/25*5=5.4kgm^2s^-1$

A solid disk, spinning counter-clockwise, has a mass of 6 kg6 kg and a radius of 3/5 m3/5 m. If a point on the edge of the disk is moving at 3 m/s3 m/s in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?