A solid disk, spinning counter-clockwise, has a mass of $9 kg$ and a radius of $4 m$ . If a point on the edge of the disk is moving at $15 m/s$ in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?

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Answer 1 · 2017-01-14T11:05:19

The angular momentum is $=1696.5kgms^(-1)$
The angular velocity is $=23.6rads^-1$

The angular velocity is

$omega=v/r$

where,

$v=15ms^(-1)$

$r=4m$

So,

$omega=15/4*2pi=15/2pi=23.6rads^-1$

The angular momentum is $L=Iomega$

For a solid disc, $I=(mr^2)/2$

So, $I=9*(4)^2/2=72kgm^2$

$L=15/2pi*72=1696.5kgms^(-1)$

A solid disk, spinning counter-clockwise, has a mass of 9 kg9 kg and a radius of 4 m4 m. If a point on the edge of the disk is moving at 15 m/s15 m/s in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?