A triangle has corners at $(1, 4 )$ , $( 2, 3 )$ , and $( 5 , 2 )$ . If the triangle is dilated by $3 x$ around $(1, 1)$ , what will the new coordinates of its corners be?

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A triangle has corners at $(1, 4 )$ , $( 2, 3 )$ , and $( 5 , 2 )$ . If the triangle is dilated by $3 x$ around $(1, 1)$ , what will the new coordinates of its corners be?

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Answer 1 · 2018-02-28T00:15:47

$(1, 9x +1), (3x + 1, 6x+1), (12x+1, 3x+1)$

Explanation:

Let's shift the expansion to be around the origin. Hence, the corners become $(0, 3), (1, 2), (4, 1)$ . We do this because expanding around the origin is really easy. We just multiply everything by that value.

Therefore, the expansion of these new points is $(0, 9x),(3x, 6x),(12x, 3x)$

Returning them around (1,1), we get the final solution:
$(1, 9x +1), (3x + 1, 6x+1), (12x+1, 3x+1)$

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A triangle has corners at $(1, 4 )$ , $( 2, 3 )$ , and $( 5 , 2 )$ . If the triangle is dilated by $3 x$ around $(1, 1)$ , what will the new coordinates of its corners be?

1 Answer

Explanation:

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Impact of this question

Science

Math

Humanities

... and beyond

A triangle has corners at (1, 4 )(1, 4 ), ( 2, 3 )( 2, 3 ), and ( 5 , 2 )( 5 , 2 ). If the triangle is dilated by 3 x 3 x around (1, 1)(1, 1), what will the new coordinates of its corners be?

1 Answer

Explanation:

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Impact of this question

A triangle has corners at $(1, 4 )$ , $( 2, 3 )$ , and $( 5 , 2 )$ . If the triangle is dilated by $3 x$ around $(1, 1)$ , what will the new coordinates of its corners be?