A triangle has corners at (2, 1 )(2,1), ( 1, 3 )(1,3), and (5 , 5 )(5,5). If the triangle is dilated by 3 x3x around (1, 6)(1,6), what will the new coordinates of its corners be?
2 Answers
Explanation:
The vector equation of a line from
Perform the subtraction within the vector:
The vector equation of a line from
Perform the subtraction within the vector:
The vector equation of a line from
Perform the subtraction within the vector:
Here are the 3 vector equations:
To obtain the new points, evaluate equations [1], [2], and [3] at t = 3
Explanation:
"let " A=(2,1),B=(1,3),C=(5,5)" and " D=(1,6)let A=(2,1),B=(1,3),C=(5,5) and D=(1,6)
"and " A',B',C'" be the images of A,B" and "C
"under the dilatation"
vec(DA)=ula-uld=((2),(1))-((1),(6))=((1),(-5))
rArrvec(DA')=3((1),(-5))=((3),(-15))
rArrA'=(1+3,6-15)=(4,-9)
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vec(DB)=ulb-uld=((1),(3))-((1),(6))=((0),(-3))
rArrvec(DB')=3((0),(-3))=((0),(-9))
rArrB'=(1+0,6-9)=(1,-3)
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vec(DC)=ulc-uld=((5),(5))-((1),(6))=((4),(-1))
rArrvec(DC')=3((4),(-1))=((12),(-3))
rArrC'=(1+12,6-3)=(13,3)
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