A triangle has corners at $(3, 1 )$ , $( 2, 3 )$ , and $( 5 , 6 )$ . If the triangle is dilated by $2/5 x$ around $(1, 2)$ , what will the new coordinates of its corners be?

Question

2147 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-14T02:44:26

$color(blue)("New coordinates are " (9/5, 8/5), (7/5,12/5), (13/5,18/5)$

$A(3,1), B(2,3), C(5,6), " about point " D (1,2), " dilation factor "2/5$

$A'((x),(y)) =(2/5)a - (-3/5)d =(2/5)*((3),(1)) - (-3/5)*((1),(2)) = ((9/5),(8/5))$

$B'((x),(y)) = (2/5)b - (-3/5)d = (2/5)*((2),(3)) - (-3/5)*((1),(2)) = ((7/5),(12/5))$

$C'((x),(y)) = (2/5)c - (-35)d = (2/5)*((5),(6)) - (-3/5)*((1),(2)) = ((13/5),(18/5))$

$color(blue)("New coordinates are " (9/5, 8/5), (7/5,12/5), (13/5,18/5)$

A triangle has corners at (3, 1 )(3, 1 ), ( 2, 3 )( 2, 3 ), and ( 5 , 6 )( 5 , 6 ). If the triangle is dilated by 2/5 x 2/5 x around (1, 2)(1, 2), what will the new coordinates of its corners be?