A triangle has corners at points A, B, and C. Side AB has a length of #15 #. The distance between the intersection of point A's angle bisector with side BC and point B is #8 #. If side AC has a length of #19 #, what is the length of side BC?

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Answer 1 · 2016-09-23T01:13:35

#18.1333#

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Angle-bisector theorem : #(BD)/(AB)=(DC)/(AC)#

Given that #BD=8, AB=15, AC=19#
#=> 8/15=(DC)/19#
#=> DC=8xx19/15=10.1333#

Hence, length of #BC = BD+DC=8+10.1333=18.1333#