A triangle has corners at points A, B, and C. Side AB has a length of #21 #. The distance between the intersection of point A's angle bisector with side BC and point B is #7 #. If side AC has a length of #14 #, what is the length of side BC?
1 Answer
Feb 18, 2017
Explanation:
Let D be the point on BC where the angle bisector from A, intersects with BC
Then BC = BD + DC
We know BD = 7 and require to find DC.
Applying the
#color(blue)"Angle bisector theorem"# to the triangle.
#color(red)(bar(ul(|color(white)(2/2)color(black)((AB)/(AC)=(BD)/(DC))color(white)(2/2)|)))# substitute known values into the equation.
#rArr21/14=7/(DC)#
#color(blue)"cross multiply"#
#rArr21DC=7xx14#
#rArrDC=(7xx14)/21=14/3=4 2/3#
#rArrBC=7+4 2/3=11 2/3" units"#