A triangle has sides A,B, and C. If the angle between sides A and B is 3π8, the angle between sides B and C is π12, and the length of B is 5, what is the area of the triangle?

1 Answer
Apr 15, 2016

Hence area of triangle is 3.015 units

Explanation:

The length of side B is 5 and angle opposite this side is angle between sides A and C, which is not given. But as other two angles are 3π8 and π12, this angle would be

π3π8π12=24π9π2π24=13π24

Now for using sine formula for area of triangle given by 12×ab×sinθ, we need one more side. Let us choose the side C, which is opposite the angle 3π8.

Now using sine rule we have

5sin(13π24)=Csin(3π8) or C=5×sin(3π8)sin(13π24)

Hence area of triangle is 12×5×5×sin(3π8)sin(13π24)×sin(π12)

= 252×0.9239×0.25880.9914=3.015 units