A triangle has sides A, B, and C. If the angle between sides A and B is 3π8, the angle between sides B and C is π2, and the length of B is 12, what is the area of the triangle?

1 Answer
Feb 26, 2016

A=72(1+2)

Explanation:

Lets take a look at the triangle.

GeogebraGeogebra

The area of a triangle is given by the formula;

A=12base×height

The angle π2 is a right angle, so the area of our triangle is;

A=12B×C

We are given the length of B, and we can solve for C using the tangent formula.

tanθ=CB

tan(3π8)=C12

C=12tan(3π8)

We can solve for tan(3π8) using a calculator or using the half angle formula. Since its not the emphasis of the problem, I'll just include a link to the solution here. The punch line is;

tan(3π8)=1+2

So our area function becomes;

A=12B×C=12(12)(12(1+2))

A=72(1+2)