A triangle has sides A, B, and C. If the angle between sides A and B is 3π8, the angle between sides B and C is 7π12, and the length of B is 3, what is the area of the triangle?

1 Answer
Mar 25, 2016

Area30.766 units2 to 3 dp

Explanation:

Tony B

Sum of internal angles for a triangle is 180oπ radians

So AC=124π712.o

h=Bsin(AB)=3sin(38π)2.7716

Asin(BC)=Bsin(AC)

A=Bsin(BC)sin(AC)22.201

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Area=A2×h

Area=Bsin(BC)2sin(AC)×Bsin(AB)

Area=3sin(BC)2sin(AC)×3sin(AB)30.766 to 3 dp