A triangle has sides A,B, and C. If the angle between sides A and B is 5π8, the angle between sides B and C is π12, and the length of B is 3, what is the area of the triangle?

1 Answer
Feb 6, 2016

Area =1.356 units2 to 3 decimal places

Explanation:

Tony B

Method

Find h using the sin rule. Then use h to determine the area.

Solution

Target is to be able to apply Csin(c)=Bsin(b)

To do this we need to find cba

The sum of the internal angles in a triangle is 180o

cba=π5π8π12=7π24 (52.5o)

Thus we have

Csin(5π8)=3sin(7π24)

C=3×sin(5π8)sin(7π24)

h=Csin(π12)

h=3×sin(5π8)sin(7π24)×sin(π12)

Area=B2×h = 92×sin(5π8)sin(7π24)×sin(π12)

92×sin(112.5o)sin(52.5o)×sin(15o)

=1.356 units2