A triangle has sides A, B, and C. If the angle between sides A and B is $\frac{π}{3}$ $(pi)/3$ , the angle between sides B and C is $\frac{π}{3}$ $pi/3$ , and the length of B is 17, what is the area of the triangle?

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Answer 1 · 2016-03-07T08:19:47

Area $= \frac{\sqrt{3}}{4} \cdot 17^{2} = \frac{289 \sqrt{3}}{4} = 125.141$ $=sqrt3/4*17^2=(289sqrt3)/4=125.141" "$ square units

The triangle is an equiangular triangle with all angles $= \frac{π}{3} = 60^{\circ}$ $=pi/3=60^@$

Formula for the area $= \frac{\sqrt{3}}{4} \cdot s^{2}$ $=sqrt3/4*s^2$

with side $s = 17$ $s=17$

we compute the Area $= \frac{\sqrt{3}}{4} \cdot 17^{2} = \frac{289 \sqrt{3}}{4} = 125.141$ $=sqrt3/4*17^2=(289sqrt3)/4=125.141" "$ square units

God bless.... I hope the explanation is useful.

A triangle has sides A, B, and C. If the angle between sides A and B is π3(pi)/3, the angle between sides B and C is π3pi/3, and the length of B is 17, what is the area of the triangle?