A triangle has sides A,B, and C. If the angle between sides A and B is $\frac{π}{6}$ $(pi)/6$ , the angle between sides B and C is $\frac{π}{6}$ $pi/6$ , and the length of B is 7, what is the area of the triangle?

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Answer 1 · 2017-06-21T13:25:25

The area of the triangle is $= 3.03 u^{2}$ $=3.03u^2$

The triangle is an isoceles triangle.

The angle betwwen side $A$ $A$ and side $C$ $C$ is

$= π - (\frac{1}{6} π + \frac{1}{6} π)$ $=pi-(1/6pi+1/6pi)$

$= \frac{2}{3} π$ $=2/3pi$

The height of the triangle is

$h = \frac{3}{2} tan (\frac{1}{6} π)$ $h=3/2tan(1/6pi)$

The area of the triangle is

$A = \frac{1}{2} \cdot b \cdot h$ $A=1/2*b*h$

$= \frac{1}{2} \cdot 7 \cdot \frac{3}{2} tan (\frac{1}{6} π)$ $=1/2*7*3/2tan(1/6pi)$

$= \frac{21}{4} tan (\frac{1}{6} π)$ $=21/4tan(1/6pi)$

$= 3.03$ $=3.03$

A triangle has sides A,B, and C. If the angle between sides A and B is π6(pi)/6, the angle between sides B and C is π6pi/6, and the length of B is 7, what is the area of the triangle?