A triangle has sides A, B, and C. Sides A and B have lengths of 1 and 4, respectively. The angle between A and C is $(5pi)/24$ and the angle between B and C is $(13pi)/24$ . What is the area of the triangle?

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Answer 1 · 2017-06-13T12:58:44

The area of the triangle is $=sqrt2=1.41u^2$

The angle between $A$ and $C$ is

$=pi-(5/24pi+13/24pi)$

$=pi-18/24pi$

$=6/24pi=1/4pi$

The area of the triangle $DeltaABC$ is

$=1/2*A*B*sin(1/4pi)$

$=1/2*1*4*sqrt2/2$

$=sqrt2$

$=1.41$

A triangle has sides A, B, and C. Sides A and B have lengths of 1 and 4, respectively. The angle between A and C is (5pi)/24(5pi)/24 and the angle between B and C is (13pi)/24 (13pi)/24. What is the area of the triangle?