A triangle has sides A, B, and C. Sides A and B have lengths of 12 and 1, respectively. The angle between A and C is $\frac{7 π}{24}$ $(7pi)/24$ and the angle between B and C is $\frac{7 π}{24}$ $(7pi)/24$ . What is the area of the triangle?

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Answer 1 · 2018-02-17T08:34:27

It’s an isosceles triangle and a must equal b;

But given $a = 12, b = 1$ $a = 12, b = 1$ , hence measurements aren’t in order.

Given $a = 12, ˆ A = \frac{7 π}{24}, b = 1, ˆ B = \frac{7 π}{24}$ $a = 12, hatA = (7pi)/24, b = 1, hatB = (7pi)/24$

Since $ˆ A = ˆ B$ $hatA = hatB$ , it’s an isosceles triangle.

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Hence a must equal b

But given $a = 12, b = 1$ $a = 12, b = 1$ , measurements aren’t in order.

A triangle has sides A, B, and C. Sides A and B have lengths of 12 and 1, respectively. The angle between A and C is 7π24(7pi)/24 and the angle between B and C is 7π24 (7pi)/24. What is the area of the triangle?