A triangle has sides A, B, and C. Sides A and B have lengths of 2 and 1, respectively. The angle between A and C is $\frac{13 π}{24}$ $(13pi)/24$ and the angle between B and C is $\frac{3 π}{8}$ $(3pi)/8$ . What is the area of the triangle?

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Answer 1 · 2017-03-05T09:33:27

the area is $\frac{\sqrt{6} - \sqrt{2}}{4}$ $(sqrt6-sqrt2)/4$

The angle between A and B is:

$ˆ A B = π - \frac{13}{24} π - \frac{3}{8} π = \frac{2}{24} π = \frac{1}{12} π$ $hat(AB)=pi-13/24pi-3/8pi=2/24pi=1/12pi$

The area of the triangle is:

$1/2A*B*sin(hat(AB))=1/cancel2*cancel2*1*sin(pi/12)$

$(sqrt6-sqrt2)/4$

A triangle has sides A, B, and C. Sides A and B have lengths of 2 and 1, respectively. The angle between A and C is (13pi)/2413π24(13pi)/24 and the angle between B and C is (3pi)/83π8 (3pi)/8. What is the area of the triangle?