A triangle has sides A, B, and C. Sides A and B have lengths of 3 and 4, respectively. The angle between A and C is $(5pi)/24$ and the angle between B and C is $(5pi)/24$ . What is the area of the triangle?

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Answer 1 · 2018-07-07T11:46:07

The triangle is not feasible.

The length of sides $A and B$ are $3 ,4$ unit respectively.

Angle between Sides $A and C$ is $/_b= (5 pi)/24==(5*180)/24=900/24=37.5^0$

Angle between Sides $B and C$ is $/_a= (5 pi)/24==(5*180)/24=900/24=37.5^0$

Since $/_b and /_a$ are equal , the triangle must be isosceles of

which opposite sides $B and A$ should be of equal length.

Here $B !=A ;(4 !=3)$ Therefore the triangle is not possible. [Ans]

A triangle has sides A, B, and C. Sides A and B have lengths of 3 and 4, respectively. The angle between A and C is (5pi)/24(5pi)/24 and the angle between B and C is (5pi)/24 (5pi)/24. What is the area of the triangle?