A triangle has sides A, B, and C. Sides A and B have lengths of 5 and 3, respectively. The angle between A and C is $\frac{π}{2}$ $(pi)/2$ and the angle between B and C is $\frac{π}{8}$ $(pi)/8$ . What is the area of the triangle?

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Answer 1 · 2018-02-17T10:09:16

As $ˆ B (\frac{π}{2}) > ˆ A ((\frac{π}{8})$ $hatB (pi/2) > hatA ((pi/8)$ , side b (3) must be greater than side a (5).

Since it’s not so, given measurements do not satisfy the conditions of a triangle.

Given : $a = 5, b = 3, ˆ A = \frac{π}{8}, ˆ B = \frac{π}{2}$ $a = 5, b = 3, hatA = pi/8, hat B = pi/2$

It’s a right triangle.

Greater side will have greater angle opposite to it.

As $ˆ B (\frac{π}{2}) > ˆ A ((\frac{π}{8})$ $hatB (pi/2) > hatA ((pi/8)$ , side b (3) must be greater than side a (5).

Since it’s not so, given measurements do not satisfy the conditions of a triangle.

A triangle has sides A, B, and C. Sides A and B have lengths of 5 and 3, respectively. The angle between A and C is π2(pi)/2 and the angle between B and C is π8 (pi)/8. What is the area of the triangle?