A triangle has sides A, B, and C. Sides A and B have lengths of 5 and 8, respectively. The angle between A and C is $(13pi)/24$ and the angle between B and C is $(3pi)/8$ . What is the area of the triangle?

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Answer 1 · 2018-03-27T02:21:46

$A_t = (1/2) * a * b * sin C = 5.18 " sq units"$

$hat B = (13pi)/24, hat A = (3pi) / 8, a = 5, b = 8$

To find the area of the triangle.

$hat C = pi - hat A - hat B = pi - (3pi) / 8 - (13pi) / 24 = pi/12$

$"Area of triangle " = A_t = (1/2) * a * b * sin C$

$A_t = (1/2) * 5 * 8 * sin (pi/12) = 5.18 " sq units"$

A triangle has sides A, B, and C. Sides A and B have lengths of 5 and 8, respectively. The angle between A and C is (13pi)/24(13pi)/24 and the angle between B and C is (3pi)/8 (3pi)/8. What is the area of the triangle?