A triangle has sides A, B, and C. Sides A and B have lengths of 5 and 9, respectively. The angle between A and C is $\frac{19 π}{24}$ $(19pi)/24$ and the angle between B and C is $\frac{π}{8}$ $(pi)/8$ . What is the area of the triangle?

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Answer 1 · 2018-03-03T02:31:47

$5.8234 unit²$

Let say a is representing angle for side A, b for side B and c for side C.

The area of triangle $= 1/2*A*B*sin c$ .

Angle c is located between side A and B, therefore
$c = pi-pi/8-19/24pi$
$c = pi-22/24 pi = 2/24pi = pi/12$

The area of triangle $= 1/2*5*9*sin(pi/12)$

$= 1/2 * 5 * 9 * 0.2588$
$= 5.8234$ unit²#

A triangle has sides A, B, and C. Sides A and B have lengths of 5 and 9, respectively. The angle between A and C is (19pi)/2419π24(19pi)/24 and the angle between B and C is (pi)/8π8 (pi)/8. What is the area of the triangle?