A triangle has sides A, B, and C. Sides A and B have lengths of 6 and 11, respectively. The angle between A and C is $\frac{19 π}{24}$ $(19pi)/24$ and the angle between B and C is $\frac{π}{24}$ $(pi)/24$ . What is the area of the triangle?

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Answer 1 · 2018-04-05T17:36:11

20.1 square units

Use area = $\frac{1}{2} \times a \times c \times sin B$ $1/2xxaxxcxxsinB$

Area= $\frac{1}{2} \times 6 \times 11 \times sin (\frac{19 π}{24})$ $1/2xx6xx11xxsin((19pi)/(24))$

Remember your calculator should be in radians

Area = 20.08912716

A triangle has sides A, B, and C. Sides A and B have lengths of 6 and 11, respectively. The angle between A and C is 19π24(19pi)/24 and the angle between B and C is π24 (pi)/24. What is the area of the triangle?