A triangle has sides A, B, and C. Sides A and B have lengths of 7 and 12, respectively. The angle between A and C is $(11pi)/24$ and the angle between B and C is $(pi)/24$ . What is the area of the triangle?

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Answer 1 · 2017-06-14T06:41:46

The area of the triangle is $=42u^2$

The angle between $A$ and $B$ is

$theta=pi-(11/24pi+1/24pi)=pi-12/24pi=1/2pi$

$sintheta=sin(1/2pi)=1$

The area of the triangle is

$A=1/2A*B*sintheta$

$=1/2*7*12*sin(pi/2)$

$=42$

A triangle has sides A, B, and C. Sides A and B have lengths of 7 and 12, respectively. The angle between A and C is (11pi)/24(11pi)/24 and the angle between B and C is (pi)/24 (pi)/24. What is the area of the triangle?