A triangle has sides A, B, and C. Sides A and B have lengths of 7 and 5, respectively. The angle between A and C is $(5pi)/24$ and the angle between B and C is $(pi)/8$ . What is the area of the triangle?

Question

1426 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-26T10:51:29

The area of the triangle is $15.16(2dp) sq.unit$

The angle between sides A and C is $/_b=(5pi)/24 =5*180/24=37.5^0$

The angle between sides B and C is $/_a=pi/8 =180/8=22.5^0$

The angle between sides A and B is $/_c=180 - (37.5+22.5)=120^0$

So we have sides $A=7 ; B=5$ and their included angle $/_c=120^0$

The area of the triangle is $A_t= (A*B*sinc)/2=(7*5*sin120)/2=15.16(2dp) sq.unit$ [Ans]

A triangle has sides A, B, and C. Sides A and B have lengths of 7 and 5, respectively. The angle between A and C is (5pi)/24(5pi)/24 and the angle between B and C is (pi)/8 (pi)/8. What is the area of the triangle?