A triangle has sides A, B, and C. Sides A and B have lengths of 8 and 3, respectively. The angle between A and C is $\frac{7 π}{24}$ $(7pi)/24$ and the angle between B and C is $\frac{17 π}{24}$ $(17pi)/24$ . What is the area of the triangle?

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Answer 1 · 2018-06-27T15:43:33

Since $ˆ C = 0$ $hat C = 0$ , with given measurements, we cannot form a triangle.

$ˆ A = \frac{17 π}{24}, a = 8, ˆ B = \frac{7 π}{24}, b = 3$ $hat A = (17pi)/24, a = 8, hat B = (7pi)/24, b = 3$

$:. hat C = pi - (17pi)/24 - (7pi)/24 = 0$

For a triangle to exist, sum of the three angles must equal $pi^c$

Since $hat C = 0$ , with given measurements, we cannot form a triangle.

A triangle has sides A, B, and C. Sides A and B have lengths of 8 and 3, respectively. The angle between A and C is (7pi)/247π24(7pi)/24 and the angle between B and C is (17pi)/2417π24 (17pi)/24. What is the area of the triangle?