A triangle has sides A, B, and C. The angle between sides A and B is #(3pi)/4#. If side C has a length of #8 # and the angle between sides B and C is #pi/12#, what are the lengths of sides A and B?

1 Answer
Mar 18, 2018

#A = 2.93#
#B = 5.66#

Explanation:

Given two angles, the third one in a triangle is fixed. In this case it is #2pi/12#. The shortest side length will be opposite the smallest angle, which is #pi/12# in this case. We know that the side of length 8 is opposite the #9pi/12# corner.

We now have three angles and a side, and can calculate the other sides using the Law of Sines, and then calculate the height for the area.
https://www.varsitytutors.com/hotmath/hotmath_help/topics/law-of-sines

https://www.mathsisfun.com/algebra/trig-solving-asa-triangles.html

#a/(sin(pi/12)) = c/sin C = 8/(sin(9pi/12))#
#b/(sin(2pi/12)) = c/sin C = 8/(sin(9pi/12))#

#a xx (sin(9pi/12)) = 8 xx (sin(pi/12))#

#b xx (sin(9pi/12)) = 8 xx (sin(2pi/12))#

#a xx 0.707 = 8 xx 0.259# ; #a = 2.93#
#b xx 0.707 = 8 xx 0.50# ; #b = 5.66#