A triangle has sides A, B, and C. The angle between sides A and B is 3π4. If side C has a length of 8 and the angle between sides B and C is π12, what are the lengths of sides A and B?

1 Answer
Mar 18, 2018

A=2.93
B=5.66

Explanation:

Given two angles, the third one in a triangle is fixed. In this case it is 2π12. The shortest side length will be opposite the smallest angle, which is π12 in this case. We know that the side of length 8 is opposite the 9π12 corner.

We now have three angles and a side, and can calculate the other sides using the Law of Sines, and then calculate the height for the area.
https://www.varsitytutors.com/hotmath/hotmath_help/topics/law-of-sines

https://www.mathsisfun.com/algebra/trig-solving-asa-triangles.html

asin(π12)=csinC=8sin(9π12)
bsin(2π12)=csinC=8sin(9π12)

a×(sin(9π12))=8×(sin(π12))

b×(sin(9π12))=8×(sin(2π12))

a×0.707=8×0.259 ; a=2.93
b×0.707=8×0.50 ; b=5.66