A triangle has sides A, B, and C. The angle between sides A and B is $\frac{5 π}{6}$ $(5pi)/6$ and the angle between sides B and C is $\frac{π}{12}$ $pi/12$ . If side B has a length of 17, what is the area of the triangle?

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A triangle has sides A, B, and C. The angle between sides A and B is $\frac{5 π}{6}$ $(5pi)/6$ and the angle between sides B and C is $\frac{π}{12}$ $pi/12$ . If side B has a length of 17, what is the area of the triangle?

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Answer 1 · 2017-09-27T18:11:50

$\frac{289}{4}$ $289/4$

Explanation:

This triangle is a isosceles triangle because the angle between sides A and C is $\frac{π}{12}$ $pi/12$ too. 【 $π$ $pi$ -( $5 π$ $5pi$ $/ 6$ $/6$ + $\frac{π}{12}$ $pi/12$ )= $\frac{π}{12}$ $pi/12$ 】

The area of the triangle $S$ $S$ is given as below:
$S$ $S$ = $\frac{1}{2}$ $1/2$ $a b sin C$ $ab sinC$
Now put $a = b = 17$ $a=b=17$ and $C=5π$ $/6$ to get the answer.

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A triangle has sides A, B, and C. The angle between sides A and B is $\frac{5 π}{6}$ $(5pi)/6$ and the angle between sides B and C is $\frac{π}{12}$ $pi/12$ . If side B has a length of 17, what is the area of the triangle?

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A triangle has sides A, B, and C. The angle between sides A and B is (5pi)/65π6(5pi)/6 and the angle between sides B and C is pi/12π12pi/12. If side B has a length of 17, what is the area of the triangle?

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Explanation:

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A triangle has sides A, B, and C. The angle between sides A and B is $\frac{5 π}{6}$ $(5pi)/6$ and the angle between sides B and C is $\frac{π}{12}$ $pi/12$ . If side B has a length of 17, what is the area of the triangle?