A triangle has sides A, B, and C. The angle between sides A and B is (7pi)/12 and the angle between sides B and C is pi/12. If side B has a length of 3, what is the area of the triangle?

1 Answer
Binayaka C.
May 28, 2016

The area of the triangle is 1.30 units^2

Explanation:

The angle between sides A and B is /_C=7*180/12=105^0
The angle between sides B and C is /_A=180/12=15^0
The angle between sides C and A is /_B=180-(105+15)=60^0
B=3 (given) We know B/sinB=C/sinC or C =3*sin105/sin60=3.35
Now B=3 ;C=3.35 and their included angle/_A=15^0 so Area =1/2 B*C*sinA =(3*3.35)/2*sin15=1.30(2dp) units^2[Ans]

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