A triangle has sides A, B, and C. The angle between sides A and B is $(7pi)/12$ and the angle between sides B and C is $pi/12$ . If side B has a length of 19, what is the area of the triangle?

Question

1806 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-02-17T09:04:20

$a = (1/2) a b sin C ~~ color(purple)(5.6783$

$hatC = (7pi)/12, hatA = pi/12, b = 19$

$hatB = pi - pi/12 - (7pi)/12 = pi/3$

$a / sin A = b / sin B$

enter image source here

$a = (1/2) a b sin C = (19 * sin (pi/12)) / sin(pi/3) ~~ color(purple)(5.6783$

A triangle has sides A, B, and C. The angle between sides A and B is (7pi)/12(7pi)/12 and the angle between sides B and C is pi/12pi/12. If side B has a length of 19, what is the area of the triangle?