A triangle has sides A, B, and C. The angle between sides A and B is $\frac{7 π}{12}$ $(7pi)/12$ . If side C has a length of $25$ $25$ and the angle between sides B and C is $\frac{π}{12}$ $pi/12$ , what is the length of side A?

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Answer 1 · 2018-05-31T07:05:46

Side a=6.6987298106

$\frac{25}{sin (\frac{7 π}{12})} = \frac{a}{sin (\frac{π}{12})}$ $(25)/(sin((7pi)/(12)))=a/(sin(pi/12))$

$\frac{25}{sin (\frac{7 π}{12})} \times sin (\frac{π}{12}) = a$ $(25)/(sin((7pi)/(12)))xx sin(pi/12)=a$

a=6.6987298106

A triangle has sides A, B, and C. The angle between sides A and B is (7pi)/127π12(7pi)/12. If side C has a length of 25 2525 and the angle between sides B and C is pi/12π12pi/12, what is the length of side A?