A triangle has sides A, B, and C. The angle between sides A and B is $(7pi)/12$ . If side C has a length of $2$ and the angle between sides B and C is $pi/12$ , what is the length of side A?

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A triangle has sides A, B, and C. The angle between sides A and B is $(7pi)/12$ . If side C has a length of $2$ and the angle between sides B and C is $pi/12$ , what is the length of side A?

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Answer 1 · 2016-06-21T10:53:24

Length of side A is $0.54 (2dp)$ unit

Explanation:

The angle between sides A and B is $/_C = (7 pi)/12 =105^0$
The angle between sides B and C is $/_A = pi/12 =15^0$
$C=2$ (given) .Applying sine law $A/sinA=C/sinC$ we get $A= 2*(sin15/sin105) = 0.54 (2 dp)$ unit [Ans]

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A triangle has sides A, B, and C. The angle between sides A and B is $(7pi)/12$ . If side C has a length of $2$ and the angle between sides B and C is $pi/12$ , what is the length of side A?

1 Answer

Explanation:

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A triangle has sides A, B, and C. The angle between sides A and B is (7pi)/12(7pi)/12. If side C has a length of 2 2 and the angle between sides B and C is pi/12pi/12, what is the length of side A?

1 Answer

Explanation:

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A triangle has sides A, B, and C. The angle between sides A and B is $(7pi)/12$ . If side C has a length of $2$ and the angle between sides B and C is $pi/12$ , what is the length of side A?