A triangle has sides A, B, and C. The angle between sides A and B is $(7pi)/12$ . If side C has a length of $19$ and the angle between sides B and C is $pi/12$ , what is the length of side A?

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Answer 1 · 2017-07-23T09:51:56

The length is $=5.09u$

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The angles are

$hatA=1/12pi$

$hatC=7/12pi$

Therefore,

$hatB=pi-(1/12pi+7/12pi)=pi-8/12pi=4/12pi=1/3pi$

The sides are

$c=19$

We apply the sine rule to the triangle

$a/sin hatA=c/sin hatC$

$a=c*sin hatA/sin hat C$

$=19*sin(1/12pi)/sin(7/12pi)$

$=5.09$

A triangle has sides A, B, and C. The angle between sides A and B is (7pi)/12(7pi)/12. If side C has a length of 19 19 and the angle between sides B and C is pi/12pi/12, what is the length of side A?