A triangle has sides A, B, and C. The angle between sides A and B is $(7pi)/12$ . If side C has a length of $15$ and the angle between sides B and C is $pi/12$ , what is the length of side A?

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A triangle has sides A, B, and C. The angle between sides A and B is $(7pi)/12$ . If side C has a length of $15$ and the angle between sides B and C is $pi/12$ , what is the length of side A?

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Answer 1 · 2016-03-25T11:37:13

The length of side $A =4.0$

Explanation:

Opposite angle of side A is $/_A=180/12=15^0$
Opposite angle of side C is $/_C=7*180/12=105^0$
Applying sine law we get $A/sinA=C/sinC or A=15*(sin15/sin105)=4.0$ [Ans]

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A triangle has sides A, B, and C. The angle between sides A and B is $(7pi)/12$ . If side C has a length of $15$ and the angle between sides B and C is $pi/12$ , what is the length of side A?

1 Answer

Explanation:

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A triangle has sides A, B, and C. The angle between sides A and B is (7pi)/12(7pi)/12. If side C has a length of 15 15 and the angle between sides B and C is pi/12pi/12, what is the length of side A?

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A triangle has sides A, B, and C. The angle between sides A and B is $(7pi)/12$ . If side C has a length of $15$ and the angle between sides B and C is $pi/12$ , what is the length of side A?