A triangle has sides A, B, and C. The angle between sides A and B is (pi)/3. If side C has a length of 14 and the angle between sides B and C is ( 3 pi)/8, what are the lengths of sides A and B?

1 Answer
bp
Feb 14, 2017

a= 14.94 ; b=12.83

Explanation:

The measurements as given in the question are depicted in the figure below

:enter image source here

To determine sides 'a' and 'b', it is obvious that sine rule would be helpful here. Thus,
sin A /a = sin B /b = Sin C/c. Here A is(3pi)/8 C ispi/3 and B is (pi-(3pi)/8- pi/3) = (7pi)/24

(sin ((3pi)/8))/a= (sin ((7pi)/24))/b= sin(pi/3)/14=sqrt3/28

0.9238/a =0.7933/b= 0.0618

This gives a= 14.94 ; b=12.83

Related questions
See all questions in The Law of Sines
Impact of this question
1307 views around the world
You can reuse this answer
Creative Commons License