A triangle has sides A, B, and C. The angle between sides A and B is pi/3. If side C has a length of 8 and the angle between sides B and C is pi/12, what is the length of side A?

1 Answer
May 18, 2017

Acolor(white)(00)pi/12color(white)(00000)acolor(white)(00)color(red)(2.391)

Bcolor(white)(00)color(black)((7pi)/12)color(white)(00000)bcolor(white)(00)8.923

Ccolor(white)(00)pi/3color(white)(0)color(white)(00000)c color(white)(00)8

Explanation:

Let's write this information in a table, where capital letters correspond to angles , lowercase to lengths :

Acolor(white)(00)pi/12color(white)(00000)acolor(white)(00)

Bcolor(white)(00)color(white)(pi/12)color(white)(00000)bcolor(white)(00)

Ccolor(white)(00)pi/3color(white)(0)color(white)(00000)c color(white)(00)8

All angles in a triangle add up to 180^o, or pi

pi/12+pi/3 only equals (5pi)/12.

(12pi)/12-(5pi)/12=(7pi)/12

That's the remaining angle:

Acolor(white)(00)pi/12color(white)(00000)acolor(white)(00)

Bcolor(white)(00)color(black)((7pi)/12)color(white)(00000)bcolor(white)(00)

Ccolor(white)(00)pi/3color(white)(0)color(white)(00000)c color(white)(00)8

We can use law of sines to find the other lengths:

(sin(pi/3))/8=(sin(pi/12))/a

a~~2.391

Just, for fun, let's also find length b

(sin(pi/3))/8=(sin((7pi)/12))/b

b~~8.923