A triangle has sides A, B, and C. The angle between sides A and B is pi/8π8. If side C has a length of 2 2 and the angle between sides B and C is pi/12π12, what is the length of side A?

2 Answers
Jan 5, 2016

The length of aa is 4/343

Explanation:

We are able to solve it using logic:
Since pi/8 = 2π8=2 we'll multiply both sides by 8 resulting in pi = 16π=16.

Then, another logic: pi = 16π=16, so pi/12 = 16/12 = 4/3π12=1612=43.

I won't say units, its implicit.

Jan 5, 2016

a=1.3524a=1.3524 units

Explanation:

First of all let me denote the sides with small letters a, b and c
Let me name the angle between side "a" and "b" by /_ CC, angle between side "b" and "c" /_ AA and angle between side "c" and "a" by /_ BB.

Note:- the sign /_ is read as "angle".
We are given with /_CC and /_AA.

It is given that side c=2.c=2.

Using Law of Sines
(Sin/_A)/a=(sin/_C)/csinAa=sinCc

implies Sin(pi/12)/a=sin((pi)/8)/2sin(π12)a=sin(π8)2

implies 0.2588/a=0.3827/20.2588a=0.38272

implies 0.2588/a=0.191350.2588a=0.19135

implies a=1.3524a=1.3524 units

Therefore, side a=1.3524a=1.3524 units