A triangle has sides with lengths: 14, 9, and 4. How do you find the area of the triangle using Heron's formula?

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Answer 1 · 2018-08-03T03:31:46

$The sides with this length does not perform the triangle.$ $"The sides with this length does not perform the triangle."$
$b + c < a$ $b+c < a$

Let $△ A B C$ $triangle ABC$ be the triangle with

$a = 14, b = 9 and c = 4$ $a=14,b=9 and c=4$

The perimeter of triangle is:

$2 s = a + b + c = 14 + 9 + 4 = 27 \Rightarrow s = \frac{27}{2} = 13.5$ $2s=a+b+c=14+9+4=27=>s=27/2=13.5$

$:.s-a=13.5-14=-05$

So, let us check three sides of triangle.

$(i)a+b=14+9=23> c$

$(ii)b+c=9+4=13 < ato$ [as $a=14]$

Hence , the sides with this length does not perform the
triangle.