Aballoon contains 6.0 moles of helium. A hole in the balloon lets 4.0 moles of helium escape the balloon. How many atoms of m remain in the balloon?

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Aballoon contains 6.0 moles of helium. A hole in the balloon lets 4.0 moles of helium escape the balloon. How many atoms of m remain in the balloon?

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Answer 1 · 2016-09-03T05:44:15

If I have 6 chocolates, and give 4 away, how many chocolates do I have left?

Explanation:

Now of course you wanted the number of atoms remaining in the balloon. But the use of a $mole$ $"mole"$ specifies that number.

One mole of stuff specifies $6.022 \times 10^{23}$ $6.022xx10^23$ individual items of that stuff. To make things easier I could write $6.022 \times 10^{23} = N_{A} Avogadro's number$ $6.022xx10^23=N_A " Avogadro's number"$ , which is something that would be recognized by all chemists (including you!).

So, I am left with $2 \times N_{A}$ $2xxN_A$ helium atoms (of course helium is a mono-atomic gas). You can do the arithmetic if you like. Can you tell me the mass of gas left in the balloon?

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Aballoon contains 6.0 moles of helium. A hole in the balloon lets 4.0 moles of helium escape the balloon. How many atoms of m remain in the balloon?

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