An electric toy car with a mass of 2 kg2kg is powered by a motor with a voltage of 3 V3V and a current supply of 7 A7A. How long will it take for the toy car to accelerate from rest to 3/2 m/s32ms?

2 Answers
Jul 17, 2017

The time is =0.11s=0.11s

Explanation:

The power is

P=UIP=UI

The voltage is U=3VU=3V

The current is I=7AI=7A

The power is

P=UI=3*7=21WP=UI=37=21W

The kinetic energy of the car is

E=1/2mv^2E=12mv2

The mass is m=2kgm=2kg

The speed is v=3/2ms^-1v=32ms1

so,

E=1/2*2*(3/2)^2=2.25JE=122(32)2=2.25J

Let the time =ts=ts

E=PtE=Pt

t=E/P=2.25/21=0.11st=EP=2.2521=0.11s

Jul 17, 2017

t= 0,107 s

Explanation:

the final kinetic energy of the car is E_K = 1/2 mv^2 = 1/2 2 kg xx (1,5 m/s)^2= 2,25 JEK=12mv2=122kg×(1,5ms)2=2,25J
the power supplied is P= V xx I=3 V xx 7A = 21 WP=V×I=3V×7A=21W
since P=E/t you have t = E/P = (2,25J)/ (21 W) = 0,107 s t=EP=2,25J21W=0,107s